Stabiliti raportul masic in care trebuie sa se amestece oleum(20% SO3) cu o solutie de H2SO4 cu concentratia(c%)=60% astfel incat concentratia noii solutii sa devina 80%.
Rezolvare:
__x__ _0,225x_ _98x_
SO3 + H2O => H2SO4
80g 18g 98g
60=md/ms *100=>md=0,6* ms/100=0,6 ms =>mH2O =ms-md=0,4ms
100g oleum............20g SO3 .................80g H2SO4
5x..............................x..........................4x
mH2O
final =0,4ms-0,225x
mdfinal =1,225x+0,6ms+4x=5,225x+0,6ms
msfinal=5x+ms
cfinala=80%=mdfinal /msfinal =>80=(5,225x+0,6ms/5x+ms) * 100=> 80(5x+ms)=100(5,225+0,6ms)=>40x+8mg=52,25x+6ms=>2ms=12,25x=>ms=12,25x/2=6,125x
5x/ms=5x/6,125x=0,8163
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